P Xxvii 2014 10a -

Let the Volume of Jug A be $V_A$ and Volume of Jug B be $V_B$. $$ \frac{V_A}{V_B} = \frac{8}{27} $$

Calculate the cube: $$ k^3 = \frac{2^3}{3^3} = \frac{8}{27} $$ Use the formula relating the volumes: $$ \frac{\text{Volume of A}}{\text{Volume of B}} = \text{Volume Ratio} $$ p xxvii 2014 10a

Based on the reference , this corresponds to a question from the Cambridge IGCSE Mathematics (0580) examination papers from the October/November 2014 session. Let the Volume of Jug A be $V_A$

$$ \text{Volume Ratio} = k^3 = \left(\frac{2}{3}\right)^3 $$ p xxvii 2014 10a

We know the volume of Jug A ($V_A$) is typically given as in this specific paper. We need to find $V_B$.

Substitute the values: $$ \frac{326}{V_B} = \frac{8}{27} $$